SOLUTION: {{{x^2=x+12}}}

Question 256134:
Found 3 solutions by checkley77, drk, jim_thompson5910:
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!

x^2-x-12=0
(x-4)(x3)=0
x-4=0
x=4 ans.
x+3=0
x=-3 ans.
Answer by drk(1908)   (Show Source): You can put this solution on YOUR website!
Here is the original question:
(i)
step 1 - move everything over to 1 side so it is = 0 we get
(ii)
step 2 - factor the left side to get
(iii)
step 3 - solve each parenthesis for x and we get
x-4 = 0
x = 4
x+3=0
x=-3
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

Start with the given equation.

Get every term to the left side.

Notice that the quadratic is in the form of where , , and

Let's use the quadratic formula to solve for "x":

Start with the quadratic formula

Plug in , , and

Negate to get .

Square to get .

Multiply to get

Rewrite as

Add to to get

Multiply and to get .

Take the square root of to get .

or Break up the expression.

or Combine like terms.

or Simplify.

So the solutions are or

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