SOLUTION: If a and b are roots of 7x^2 − 2002x +182 = 0 , find the value of 1/a + 1/b
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Question 252549: If a and b are roots of 7x^2 − 2002x +182 = 0 , find the value of 1/a + 1/b
Found 2 solutions by Alan3354, JimboP1977:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
If a and b are roots of 7x^2 − 2002x +182 = 0 , find the value of 1/a + 1/b
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7x^2 − 2002x +182 = 0
x^2 - 286x + 26 = 0
The roots are:
(-b + sqrt(b^2 - 4ac))/2a and
(-b - sqrt(b^2 - 4ac))/2a
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The inverses give:
2a/(-b + sqrt(b^2 - 4ac)) and
2a/(-b - sqrt(b^2 - 4ac))
The sum is:
2a*2*(-b)/(b^2 - (b^2 - 4ac)
= 4ab/(4ac)
= b/c The general solution
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For this eqn it's -11
= -11
Answer by JimboP1977(311) (Show Source): You can put this solution on YOUR website!
I made 1/a+1/b= 11 (positive)
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