SOLUTION: solve by graphing 4x^2-x+8=y or 4x^2-x+8=0 vertex= ( 1/8 , 127/16 )

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Question 249707: solve by graphing 4x^2-x+8=y or 4x^2-x+8=0 vertex= ( 1/8 , 127/16 )
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
4x^2-x+8=0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -127 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -127 is + or - .

The solution is , or
Here's your graph:

--------------------------
There are no real zeroes, so the graph doesn't help much.
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