SOLUTION: i need a little help to make sure i am doing this right. Solve: 2x-5=(the square root of) x+20 this is what i have: (2x-5)^2=x+20 4x^2-10x-10x+25=x+20 4x^2-20x+25=x+20 4x

Question 248126: i need a little help to make sure i am doing this right.
Solve: 2x-5=(the square root of) x+20
this is what i have:
(2x-5)^2=x+20
4x^2-10x-10x+25=x+20
4x^2-20x+25=x+20
4x^2-21x+5=0
(4x-1)(x-5)=0
4x-1=0 or x-5=0
x=1/4 or x=5
but the question on my review has multiple choice answers of:
a) 1/4 b)16 c) 29 or d) 5
which is the right answer or am i correct in thinking that there are 2 possible answers?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
The solutions or satisfy the equation . However, we're not guaranteed that they satisfy the original equation (as extraneous roots may have been introduced).

To see if is a solution to , simply plug it in to get:

which is NOT true

So is NOT a solution of

Similarly, plug in into to get:

Since the equation is true, this verifies that is a solution.

So the only solution is
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