SOLUTION: This question has proven very tricky, any help would be greatly appreciated. I can solve for x and y on the main problem, but cannot figure this one out. Help please!
Let f(x)
Algebra.Com
Question 246231: This question has proven very tricky, any help would be greatly appreciated. I can solve for x and y on the main problem, but cannot figure this one out. Help please!
Let f(x) = x2 - 8x + 16. Find x so that f(x) = 22
Found 3 solutions by dabanfield, scott8148, kensson:
Answer by dabanfield(803) (Show Source): You can put this solution on YOUR website!
Let f(x) = x2 - 8x + 16. Find x so that f(x) = 22
If the first term is x2 and not x^2 then:
2x-8x+16 = 22
Then solve for x.
If f(x) = x^2-8x+16 then we have
x^2-8x+16 = 22
x^2-8x-6 = 0
Then solve this quadratic for x.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
22 = x^2 - 8x + 16
0 = x^2 - 8x - 6 ___ not factorable
use quadratic formula to find x
Answer by kensson(21) (Show Source): You can put this solution on YOUR website!
Subtract 22 from each side
This doesn't factorise. Use the formula:
RELATED QUESTIONS
solve 5y-8+y=9y+23-6y I am stuck on this question any help would be greatly... (answered by user_dude2008)
Ok this is a parabola question.
What are the zeros for the equation y=-2x^2+5x+3... (answered by nerdybill)
Graph the inequality on a plane.
4x+5y<=20
I am very confused on this question.... (answered by ewatrrr)
I had this exponent problem.
3^x-2 = 81 --> 3^4 = 81
I can solve it by trial and... (answered by robertb)
I have no idea on how to do this problem any help would be greatly appreciated
Find... (answered by richwmiller)
Solve the poportion
17. 9/8 = p/48
Any help with this problem would be... (answered by jim_thompson5910,MathLover1)
I am kind of stuck on this problem... maybe someone can assist me! any help would be... (answered by Edwin McCravy,bucky)
I would appreciate anyone who can help me with this problem. I have been racking my... (answered by edjones)
Please help! I am trying to solve this question on my homework and do not know where to... (answered by stanbon)