SOLUTION: Randy is building a fence at the side of his warehouse. He has 120 m of fencing and plans to use the side of the warehouse as one side of the rectangular fenced area. What are the

Question 24591: Randy is building a fence at the side of his warehouse. He has 120 m of fencing and plans to use the side of the warehouse as one side of the rectangular fenced area. What are the dimensions of the maximum area Randy can enclose?
* I REALLY NEED HELP WITH THIS>.its due tomorrow
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Is this for a calculus class?
You don't need calculus to solve it anyway
Always draw a picture
|------------------|
|wwwwwwwwarew|
|wwwwwwhouseww|
|------------------|
|aaaafencedaaaaaa|
|------------------|
call the sides of the fenced area x. both sides are equal in a rectangle
the sum of the 2 sides is 2x
if there are 120m of fencing, the third side is 120 - 2x
so the equation for area is

expanding

try plugging in values for x to see what A is
x = 10

A = 1000
x = 20

A = 1600
x = 40

A = 1600
I get the same answer for x = 20 and x = 40, so the max must be in between,
since the curve is a parabola
x = 30

A = 1800
that is the max area in square meters, so the sides are 30 m and the third side
is 120 - 2(30) = 60 meters
check: 30 * 60 = 1800 m^2 for the area
and 2 * 30 + 60 = 120 for the length
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