SOLUTION: Find three consecutive whole numbers such that the product of the first and the second is 23 more than the third.

SOLUTION: Find three consecutive whole numbers such that the product of the first and the second is 23 more than the third.

Algebra.Com

Question 2432: Find three consecutive whole numbers such that the product of the first and the second is 23 more than the third.
Answer by usyim88hk(158) (Show Source): You can put this solution on YOUR website!
let x be the smallest number
(x)(x+1) = (x+2)+23
because the product of first two numbers is equal to the third number plus 23
so now solve it
x^2+x = x+25
x^2 = 25
x = 5
So the three numbers are 5,6 and 7
RELATED QUESTIONS
Find three consecutive natural numbers such that the sum of the first and second is 15... (answered by Fombitz)

How do I find, three consecutive odd numbers such that the sum of the first and second... (answered by CubeyThePenguin)

what are three consecutive positive numbers such that the product of the first and third, (answered by ankor@dixie-net.com)

what are three consecutive positive numbers such that the product of the first and third, (answered by CubeyThePenguin)

find three consecutive positive numbers such that the product of the first and third,... (answered by HasanSahin)

Find three consecutive positive integers such that the product of the first and third,... (answered by ankor@dixie-net.com,checkley77)

Find three consecutive positive integers such that the product of the first and third,... (answered by ankor@dixie-net.com)

Find three consecutive natural numbers such that the sum of the first and second is15... (answered by josgarithmetic)

Find three consecutive odd integers such that the product of the second and the third... (answered by ikleyn)