SOLUTION: I got this reply back for my question....I can't find an answer unless I am doing something wrong. Thanks for checking into it for me! Question 240789: Hello, I need some help

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Question 240880: I got this reply back for my question....I can't find an answer unless I am doing something wrong. Thanks for checking into it for me!
Question 240789: Hello,
I need some help to:
1. Solve the following equation using quadratic formula
2x^2-3x-1=0
The solution set is? ________
Thanks!!
Answer by vleith(1971) About Me (Show Source):
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
1. Solve the following equation using quadratic formula
2x^2-3x-1=0
-------------
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=17 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 1.78077640640442, -0.280776406404415. Here's your graph:


= (3/4) ħsqrt(17)/4
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