SOLUTION: How would I find the real-number solutions of the equation: x^3-3x=0

Question 239736: How would I find the real-number solutions of the equation: x^3-3x=0
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
x^3 - 3x = 0

you can factor out the x to get:

x * (x^2-3) = 0

Either x is 0 or (x^2-3) is 0

x = 0 is one of the solutions.

x^2 - 3 = 0

add 3 to each side to get:

x^2 = 3

take square root of each side to get:

x = +/- sqrt(3)

those are your solutions.

x = 0
x = sqrt(3)
x = -sqrt(3)

a graph of your equation looks like this:

+/- sqrt(3) is roughly +/- 1.7632 as shown on the graph.

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