SOLUTION: Determine the values of p for which one root of the equation
x2 - 12x + p = 0 (x2 = x squared)
is 2 more than the other root.
Many thanks.
Walker
Algebra.Com
Question 238424: Determine the values of p for which one root of the equation
x2 - 12x + p = 0 (x2 = x squared)
is 2 more than the other root.
Many thanks.
Walker
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
The key to this problem is to understand that is some number, call it "r", is a root then (x-r) is a factor. So we are looking for an equation of the form:
that simplifies to
and where
Fortunately expressions of the form:
are fairly simple to factor. We just look for the factors of "c" that add up to "b". So in your equation we look for a "p" whose factors add up to -12 and whose factors are 2 apart from each other. With some thought and/or trial and error we should be able to find that -5 and -7 are two apart from each other and they add up to -12. Since "p" is the product of these two factors, "p" is (-5)(-7) = 35. The final equation is:
whose roots are (-5) and (-7).
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