SOLUTION: 3x3x^2+7=0
3x^2+2x-7=0
x=-2+or-sqrt2^2-4(3)(-7)/2(3)
x=-2+or-sqrt4+84/6
x=-2+or-sqrt88/6
I am stuck at this point do I break the radicand 4*22?
Thank you,
Tina
Algebra.Com
Question 237680: 3x3x^2+7=0
3x^2+2x-7=0
x=-2+or-sqrt2^2-4(3)(-7)/2(3)
x=-2+or-sqrt4+84/6
x=-2+or-sqrt88/6
I am stuck at this point do I break the radicand 4*22?
Thank you,
Tina
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
You're ok except that:
so you can simplify the solutions a bit more:
or
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