SOLUTION: how would you graph the following fuctions? 1) y=1/2(x-3)2 +1 and y=-(x+4)2 -5 ?

Question 23682: how would you graph the following fuctions?
1) y=1/2(x-3)2 +1
and y=-(x+4)2 -5 ?
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
You probably already know that the graph of looks like this:

Well, these graphs will be similar, but because of the (x-3) you will be moving the graph of y =x^2 to the RIGHT 3 units. Because of the +1 added to the end of the equation, the graph will be moved UP 1 unit. And because of the 1/2 coefficient, it opens up the graph and makes it wider.

For your second graph, it says , the (x+4) moves the graph to the LEFT 4, the -5 at the end of the equation moves the graph DOWN 5 units, and the negative coefficient in front of the squared term INVERTS the graph! It should look like this:

R^2 at SCC

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