SOLUTION: I am just not understanding these type of problems. For this problem I need to use the discriminate to determine the number of solutions of the quadratic equation, and whether the

Question 234850: I am just not understanding these type of problems. For this problem I need to use the discriminate to determine the number of solutions of the quadratic equation, and whether the solutions are real or complex. It is not necessary to find the roots; just determine the number and types of solutions.
z^2+z+1=0
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
For this problem I need to use the discriminate to determine the number of solutions of the quadratic equation, and whether the solutions are real or complex. It is not necessary to find the roots; just determine the number and types of solutions.
:
You have to know the rules of the discriminate
we are talking about the quadratic form y = ax^2 = bx + c
:
The discriminate formula
d = b^2 - 4 * a * c
If d is positive: two real roots
If d = 0: two equal and real roots
If d = less than 0, (neg) no real roots, (complex)
:
z^2 + z + 1
:
In this problem
a = 1
b = 1
c = 1
:
The discriminate
d =
d = 1 - 4
d = -3, negative, no real roots, complex

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