SOLUTION: Find the x- and y-intercepts. If no x-intercepts exist, state so f(x) = x2 - 6x + 17 (Points: 3) a No x-intercepts, (0, 17) b No x-intercepts, (0, -17) c (

Question 233414: Find the x- and y-intercepts. If no x-intercepts exist, state so
f(x) = x2 - 6x + 17 (Points: 3)
a No x-intercepts, (0, 17)
b No x-intercepts, (0, -17)
c (6√104)/2 (0, -17)
d (6√104)/2, (0, 17)

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
f(x) = x2 - 6x + 17

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -32 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -32 is + or - .

The solution is , or
Here's your graph:

--------------
The y-intercept is f(0) = 17
There are no x-intercepts.

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