SOLUTION: This is my problem What is the "Vertex" & Sketch its graph y = -3x^2 + 6x Thanks, Paul

Question 23313: This is my problem
What is the "Vertex" & Sketch its graph
y = -3x^2 + 6x
Thanks,
Paul
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
There are several ways to find the vertex of this. I think the easiest way is to use a formula for the vertex that comes from the quadratic formula. Remember that? Well, this formula is just the first part of this without the radical. It turns out the vertex of a parabola (which opens up or down!) is always at

In your case, , a=-3 and b=6, so .

Now, if x=1, then

Vertex is at (1,3).

Check it out with the graph:

Does this graph look like the vertex is at (1,3), and does the graph open down?

R^2 at SCC.
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