SOLUTION: How so you solve this equation X^4+3x^3-8x-24=0?

Question 230818: How so you solve this equation X^4+3x^3-8x-24=0?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Most classroom problems of this type have integer solutions.
The last term is 24, so try 1, 2, 3, 4, 6 until you find one (it could be + or minus).
2 is a solution, so divide by (x-2).
--> x^3 + 5x^2 + 10x + 12
-3 is a solution, divide by (3+3)
--> x^2 + 2x + 4

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -12 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -12 is + or - .

The solution is , or
Here's your graph:

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