SOLUTION: find the maximum revenue for the revnue function R(x)= 140x

SOLUTION: find the maximum revenue for the revnue function R(x)= 140x - 0.02 x to the second power.

Question 2302: find the maximum revenue for the revnue function R(x)= 140x - 0.02 x to the second power.
Answer by matthew_sessoms(39) (Show Source): You can put this solution on YOUR website!
You can graph this or use the "complete the square" (CTS) method. I'll do both. I won't go into detail how to "complete the square" but rather show my steps. If you're not familiar with CTS, write back and I'll tell you.

R(x)=140x-.02x^2
y=-.02x^2+140x

Factor out the -.02

This is now in the form of: , where (h,k) is the vertex. "k" is the maximum if "a" is negative. "k" is the minimum if "a" is positive.

So, (3500, 245000) is the vertex.
245000 is the maximum
Here is the graph to prove my statements.

MS
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