SOLUTION: solve by completing the square
9X^2 +18x-5
now i divide 9 into 9x^2 , 18x and -5 to get
x^2 +2x -5/9
then i square of -5/9 to get -5/3 and i got stuck becaus
Algebra.Com
Question 228018: solve by completing the square
9X^2 +18x-5
now i divide 9 into 9x^2 , 18x and -5 to get
x^2 +2x -5/9
then i square of -5/9 to get -5/3 and i got stuck because my book says that by squaring x ^2 +2 its suppose to equal to -1/3
anyone can give me a full break down why the answer to 9x^2 +18x=-5x is
-1/3, -5/3
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
9X^2 +18x-5
now i divide 9 into 9x^2 , 18x and -5 to get
x^2 + 2x - 5/9 = 0
:
x^2 + 2x + ___ =
:
Complete the square, divide the coefficient of 2 by 2 and square (2/2)^2 = 1
x^2 + 2x + 1 = + 1; added 1 to both sides
:
x^2 + 2x + 1 = +
:
(x + 1)^2 =
:
Find the square root of both sides
x + 1 = +/-
:
Extract the square root of 1/9
x + 1 = +/-
:
Two solutions
x = -1 -
and
x = -1 +
;
:
I know this is not what your book says, but that's what I get for this equation
It checked out on my Ti83
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