SOLUTION: THE PERIMETER IS 1280, THE WIDTH IS 90 LESS THAN THE LENGTH, WHAT IS THE LENGTH AND WIDTH?

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Question 225944: THE PERIMETER IS 1280, THE WIDTH IS 90 LESS THAN THE LENGTH, WHAT IS THE LENGTH AND WIDTH?
Answer by drj(1380)   (Show Source): You can put this solution on YOUR website!
THE PERIMETER IS 1280, THE WIDTH IS 90 LESS THAN THE LENGTH, WHAT IS THE LENGTH AND WIDTH?

Step 1. The perimeter P means adding up all the four sides of a rectangle.

Step 2. Let w be the width.

Step 3. Let w+90 be the length since the width is 90 less than the length

Step 4. Then, P=w+w+w+90+w+90=1280.

Step 5. Solving yields the following steps

Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: w=275.
  • Graphical form: Equation was fully solved.
  • Text form: w+w+w+90+w+90=1280 simplifies to 0=0
  • Cartoon (animation) form:
    For tutors: simplify_cartoon( w+w+w+90+w+90=1280 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at .
Added fractions or integers together
It becomes .
Look at .
Moved 180 to the right of expression
It becomes .
Look at .
Eliminated similar terms highlight_red%28+w+%29,highlight_red%28+w+%29,highlight_red%28+w+%29,highlight_red%28+w+%29 replacing them with highlight_green%28+%281%2B1%2B1%2B1%29%2Aw+%29
It becomes .
Look at .
Added fractions or integers together
It becomes .
Look at .
Remove unneeded parentheses around factor highlight_red%28+4+%29
It becomes .
Look at .
Moved these terms to the left highlight_green%28+-1280+%29
It becomes .
Look at .
Added fractions or integers together
It becomes .
Look at .
Removed extra sign in front of -1100
It becomes .
Look at .
Solved linear equation highlight_red%28+4%2Aw-1100=0+%29 equivalent to 4*w-1100 =0
It becomes .
Result:
This is an equation! Solutions: w=275.

Universal Simplifier and Solver


Done!



For w=275 , then w+90=365 and P=2(275+365)=1280 which is a true statement.

Step 6. ANSWER: The length is 365 and the width is 275

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J

drjctu@gmail.com

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