SOLUTION: 3x^2+3x+13=0 i would like to see how you worked it out please

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Question 225280: 3x^2+3x+13=0
i would like to see how you worked it out please

Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
3x^2+3x+13=0

x=(-3+-sqrt[3^2-4*3*13])/2*3
x=(-3+-sqrt[9-156])/6
x=(-3+-sqrt-147)/6
x=(-3+-12.124i)/6
x=-3/6+-2.207i ans.

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