SOLUTION: I am trying to solve this equation C(x)=2x^2-57x + 26=0 X=50 I have tried putting the 50 in the x variable but am not sure the results C(50)= 2(50)^2 -57(50)+ 26=

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Question 224186: I am trying to solve this equation
C(x)=2x^2-57x + 26=0
X=50
I have tried putting the 50 in the x variable but am not sure the results
C(50)= 2(50)^2 -57(50)+ 26=
Found 2 solutions by RAY100, Alan3354:
Answer by RAY100(1637)   (Show Source): You can put this solution on YOUR website!
Looks good, lets review
.
C(x) = 2x^2 -57x +26
.
C(x)= 2(50)^2 -57(50) +26
.
C(50)=2* 2500 - 2850 + 26
.
C(50) = 5000 -2850 +26
.
C(x) = 2176
.
.
To check,,,just do operations in order on std calculator
.
.
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
I am trying to solve this equation
C(x)=2x^2-57x + 26=0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=3041 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 28.0363156789622, 0.463684321037762. Here's your graph:

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x = 50
C(50) = 2*2500 - 57*50 + 26
C(50) = 2176

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