SOLUTION: Give exact and approximate solutions to three decimal places. y^2-4y+4=9 Thank you!

Question 221482: Give exact and approximate solutions to three decimal places.
y^2-4y+4=9
Thank you!
Found 2 solutions by jim_thompson5910, RAY100:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Start with the given equation.

Subtract 9 from both sides.

Combine like terms.

Notice that the quadratic is in the form of where , , and

Let's use the quadratic formula to solve for "y":

Start with the quadratic formula

Plug in , , and

Negate to get .

Square to get .

Multiply to get

Rewrite as

Add to to get

Multiply and to get .

Take the square root of to get .

or Break up the expression.

or Combine like terms.

or Simplify.

So the solutions are or

If you need more help with this subject, check out this solver.
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
y^2 -4y +4 = 9
.
y^2 -4y -5 =0,,,,,,,,,,factor
.
(y-5)(y+1) =0
.
y= 5,,,-1
.
.
check,,,,(5),,,5^2 -4*5 +4 = 9,,,,,25-20 +4 =9,,,,ok
.
(-1),,,,(-1)^2 -4(-1) +4 = 1+4+4 =9,,,,,,ok
.
.
If we use thew quadratic formula
.
a= 1,,,,b=-4,,,,c=-5
.
x=[ -(-4) +/- sqrt{ (-4)^2 -4(1)(-5)}] / 2(1)
.
x=[4 +/- sqrt{ 16+20}]/2
.
x=[ 4+/- sqrt36] /2
.
x= [4 +/- 6] /2
.
x= 10/2=5,,,,,,-2/2=-1
.

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