SOLUTION: Find the solution set for N. 6n^2 + 13n + 6 = 0 a. (2/3, 3/2) b. (2/3, -3/2) c. (-2/3, -3/2) d. (-2/3, 3/2)

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Question 220175: Find the solution set for N.
6n^2 + 13n + 6 = 0
a. (2/3, 3/2)
b. (2/3, -3/2)
c. (-2/3, -3/2)
d. (-2/3, 3/2)

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for n:


Starting with the general quadratic





the general solution using the quadratic equation is:







So lets solve ( notice , , and )





Plug in a=6, b=13, and c=6




Square 13 to get 169




Multiply to get




Combine like terms in the radicand (everything under the square root)




Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




Multiply 2 and 6 to get 12


So now the expression breaks down into two parts


or


Lets look at the first part:





Add the terms in the numerator

Divide


So one answer is






Now lets look at the second part:





Subtract the terms in the numerator

Divide


So another answer is




So our solutions are:

or


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