SOLUTION: What is the quadratic equation when the vertex is (0,8)/ it is the maximum/ y-intercept is (0,8)/ the axis of symmetry is 0/ and the x-intercepts are -2 and 2

Question 215378: What is the quadratic equation when the vertex is (0,8)/ it is the maximum/ y-intercept is (0,8)/ the axis of symmetry is 0/ and the x-intercepts are -2 and 2
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
What is the quadratic equation when the vertex is (0,8)/ it is the maximum/
y-intercept is (0,8)/ the axis of symmetry is 0/ and the x-intercepts are -2 and 2
:
Using ax^2 + bx + c
This equation is difference of squares, find a, don't need b, c = 8
4a - 2b + 8 = 0; x=-2; y=0
4a + 2b + 8 = 0; x==2; y=0
----------------addition eliminates b
8a + 16 = 0
8a = -16
a = -16/8
a = -2
the equation -2x^2 + 8;
Looks like this:

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