SOLUTION: 3x^2-19x+16=0

SOLUTION: 3x^2-19x+16=0

Algebra.Com

Question 214042: 3x^2-19x+16=0
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
(3x - 16) (x - 1) = 0

x = 1 and x = 16/3
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