SOLUTION: Find three consecutive positive odd integers such that 4 times the sum of all three equals 13 more than the product of the smaller two.

Question 212034: Find three consecutive positive odd integers such that 4 times the sum of all three equals 13 more than the product of the smaller two.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find three consecutive positive odd integers such that 4 times the sum of all three equals 13 more than the product of the smaller two.
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Eequation:
4(6x+3) = (2x-1)(2x+1) + 13
24x+12 = 4x^2-1 + 13
4x^2 -24x = 0
4x(x-6) = 0
x = 0 or x = 6
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Positive solutions:
1st 2x-1 = 2*6-1 = 11
2nd : 13
4rd : 15
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Cheers,
Stan H.
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