SOLUTION: This is from a chapter on solving a quadratic equation by compleating a square. Please help me solve. {{{(4)/(m^2-7)=1}}} Thank you.

Question 211918This question is from textbook Intoductery Algebra
: This is from a chapter on solving a quadratic equation by compleating a square. Please help me solve.

Thank you. This question is from textbook Intoductery Algebra

Found 2 solutions by drj, MathTherapy:
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
This is from a chapter on solving a quadratic equation by completing a square. Please help me solve.

Step 1. For this case completing the square was not needed. Let's get rid of the denominator by multiplying the denominator to both sides of the equation.

The equation OR which will now be

Step 2. Now let's subtract -4 from both sides of the equation.

(note: the answer is just the ) plus or minus sqrt(11)

Step 3. So this is now a quadratic equation where

a=1, b=0, and c=-11 where we will use the quadratic formula

Step 4. See the steps below to solve this.

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=44 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 3.3166247903554, -3.3166247903554. Here's your graph:

Note: Step-By-Step Videos in Pre-Algebra can be found at http://www.FreedomUniversity.Tv/courses/IntroAlgebra.

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
This is from a chapter on solving a quadratic equation by compleating a square. Please help me solve.

We proceed by completing the square to solve this equation

-------> Cross-multiplying
------> Add 7 to both sides of equation
b = 0, so there is no halving "b" and then squaring the result, so move on to next step

Therefore, m = or
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