SOLUTION: solve by completing square 4 x^2 - 8x

SOLUTION: solve by completing square 4 x^2 - 8x - 2 = 0

Question 209416: solve by completing square 4 x^2 - 8x - 2 = 0
Found 2 solutions by Earlsdon, RAY100:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
SOLVE BY COMPLETING THE SQUARE:
First, divide both sides by 4 so as to get the coefficient equal to 1.
Now add to both sides.
Complete the square in x by adding the square of half the x-coefficient to both sides, that's :
Simplify.
Take the square root of both sides.
or Finally, add 1 to both sides of each solution.
or

Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
4x^2 -8x -2 =0
.
divide by 4 to get leading coefficient =1
.
x^2 -2x -1/2 =0
.
move constant to rt side
.
x^2 -2x = 1/2
.
take coefficient of 2nd term,,,divide by 2,, and square
.
(2/2)^2 =1,,,,,add to both sides of eqn
.
x^2 -2x +1 = 1/2 +1
.
(x-1)^2 = 1.5
.
take square root of both sides
.
x-1 = +/- 1.225
.
x=+1.225 +1 = 2.225,,,,,or x= -1.225 +1 = -.225
.
check(2.225),,,4(2.225)^2 -8(2.225)-2 = 0,,,,,ok
.
(-.225),,,,4(-.225)^2 -8(-.225) -2 = 0,,,,,,ok
.

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