SOLUTION: Could you please help me with this problem? Solve using the quadratic Formaula. Give exact solutions 4x^2= -20x-12 Thanks you!!!!!!!!

Question 208682:
Could you please help me with this problem?
Solve using the quadratic Formaula. Give exact solutions
4x^2= -20x-12
Thanks you!!!!!!!!
Answer by algebrapro18(249) (Show Source): You can put this solution on YOUR website!
First off we need to get this equation into standard form which is ax^2+bx+c=0. To do that we need to add 20x and 12 to both sides.

4x^2+20x+12=0. Now we can plug into the quadratic formula.

where a = 4, b = 20, and c = 12. Plugging in you get:

Now we simplify:

208 is divisible by 16 so you can take divide by 16 and then pull a 4 out because the square root of 16 is 4.
So the expression above simplifies down to

Since there is a factor of 4 present in all 3 whole numbers we can divide everything by 4. Doing so will result in:

And that is your final exact answer.
RELATED QUESTIONS
Could you please help me with this problem Solve for x:... (answered by venugopalramana)

Hi! Could you please help me with this problem? I have to find the solutions for 2x^2... (answered by Alan3354)

Could you please help me to solve this: Using the quadratic formula solve: 2x^2 + 4x - 7 (answered by josmiceli)

Tutor, I am think this is incorrect could you please help me with this problem:... (answered by jim_thompson5910)

Could someone help me with this problem "Solve using the quadratic formula... (answered by MathLover1)

Solve: 10x^2 = 20x+30 What are the solutions to the equation? Can someone please... (answered by josmiceli)

The problem is x(squared)-(minus)x-(minus)6 I figured out the solutions (x= -2, 3) by... (answered by jim_thompson5910)

Solve the quadratic equation. 4x^2 = 13x + 12 Please help! I broke it down into... (answered by scott8148)

Please help me with this problem..... Give exact and approximate solutions to three... (answered by MathLover1)