SOLUTION: A plane reaches 1200 Km 1 hr earlier, if the speed of the plane is increased by 60km/hr from its initial speed. what is the initial speed of the plane?

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Question 205849: A plane reaches 1200 Km 1 hr earlier, if the speed of the plane is increased by 60km/hr from its initial speed. what is the initial speed of the plane?
Answer by AndrewRyan(3)   (Show Source): You can put this solution on YOUR website!
(x+60) [(1200/x)-1] = 1200
1200 - x + (72000/x) - 60 = 1200
x(1200 - 60 - x + (72000/x) = 1200)
1140x - x^2 + 72000 = 1200x
-x^2 + 1140x - 1200x + 72000 = 0
-x^2 - 60x + 72000 = 0
x^2 + 60x - 72000 = 0
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=291600 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 240, -300. Here's your graph:

(x - 240)(x + 300)
x = 240; x = -300 [-300 will be ignored because there is no negative speed]
x = 240
checking:
(240+60) [(1200/240)-1] = 1200
(300) (5 - 1) = 1200
(300) (4) = 1200
1200 = 1200
x = 240 is a solution

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