SOLUTION: Can you please help me with this?
How many solutions exist for a quadratic equation and how do we determine algebraically whether the solutions are real or complex?
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Question 203638: Can you please help me with this?
How many solutions exist for a quadratic equation and how do we determine algebraically whether the solutions are real or complex?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Can you please help me with this?
How many solutions exist for a quadratic equation and how do we determine algebraically whether the solutions are real or complex?
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Every quadratic can be written in the form y = ax^2 + bx + c
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The solutions are x = [-b+-sqrt(b^2-4ac)]/(2a)
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If b^2-4ac > 0 you have two Real Number solutions.
If b^2-4ac = 0 you have two EQUAL Real Number solutions.
If b^2-4ac <0 you have two complex number solutions.
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b^2-4ac is the determinant for the quadratic
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Cheers,
Stan H.
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