SOLUTION: I need help about this one as well! If a, b, and c are three consecutive integers, find the integers if {{{c^3-a^3=866}}} in {{{a^2+c^2-2b^2=2}}}

SOLUTION: I need help about this one as well! If a, b, and c are three consecutive integers, find the integers if {{{c^3-a^3=866}}} in {{{a^2+c^2-2b^2=2}}}

Algebra.Com

Question 202023: I need help about this one as well!
If a, b, and c are three consecutive integers, find the integers if in
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
13^3 - 11^3 = 866
------------------

(a-11)*(a+13) = 0
a = 11
a = -13
-------------------
a^2+c^2-2b^2=2
11^2 + 13^2 - 2*12^2 is not 2, it's -8.
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