SOLUTION: Dear tutor,Could you help me to solving this equation please?I do not have any idea to solve it!
{{{x^4-13x^2+36=0}}}
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Question 201889: Dear tutor,Could you help me to solving this equation please?I do not have any idea to solve it!
Found 2 solutions by checkley77, jim_thompson5910:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
(x^2-9)(x^2-4)=0
(x+3)(x-3)(x+2)(x-2)=0
x+3=0
x=-3 ans.
x-3=0
x=3 ans.
x+2=0
x=-2 ans.
x-2=0
x=2 ans.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation.
Let . So
Replace with . Replace with "z"
Notice that the quadratic is in the form of where , , and
Let's use the quadratic formula to solve for "z":
Start with the quadratic formula
Plug in , , and
Negate to get .
Square to get .
Multiply to get
Subtract from to get
Multiply and to get .
Take the square root of to get .
or Break up the expression.
or Combine like terms.
or Simplify.
So the solutions in terms of "z" are or
Now recall that we let
So when , or
In other words, when , or
So the first two solutions in terms of "x" are: or
Likewise, when , or
So when , or
So the next two solutions in terms of "x" are: or
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Answer:
So the four solutions are:
, , or
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