SOLUTION: solve by completing the square:
b^2-8b-38=10
Algebra.Com
Question 201687: solve by completing the square:
b^2-8b-38=10
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Step 1:. Divide both sides by the lead coefficient. For your problem, the lead coefficient is 1, so there is nothing to do.
Step 2:. Add the opposite of the constant term on the left to both sides, i.e., combine the constant terms and put them on the right hand side:
Step 3:. Divide the coefficient on the 1st degree term by 2 and square the result, adding that value to both sides of the equation.
, so:
Step 4:. Factor the perfect square trinomial on the left:
Step 5:. Take the square root of both sides, remembering to consider both the positive and negative roots.
Step 6:. Solve
, or
John

RELATED QUESTIONS
Solve cx^2-ax=b by completing the... (answered by josgarithmetic)
Solve cx^2-ax-b by completing the... (answered by josgarithmetic)
Solve cx^2-ax=b by completing the... (answered by Timnewman)
Solve cx^2-ax=b by completing the... (answered by rothauserc)
solve each equation by completing the square b^2 -12b +45 =... (answered by waynest)
Solve by completing the square. x^2 - 22x =... (answered by asuar010)
Solve by completing the square: 3x^2 - 10=... (answered by josmiceli)
y^2+6y+10=0 solve by completing the... (answered by nerdybill,MathTherapy)
x^2 - 9x - 38 = -9 by completing the... (answered by checkley77)