SOLUTION: FIND THE VALUE OF 'X' BY QUADRATIC FORMULA 1. 9x^2-9(a+b)x+2a^2+5ab+2ab^2=0 2.a^2b^2x-(4b^4-3a^4)x-12a^2b^2=0 I WILL BE THANKFUL PRIYAL

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: FIND THE VALUE OF 'X' BY QUADRATIC FORMULA 1. 9x^2-9(a+b)x+2a^2+5ab+2ab^2=0 2.a^2b^2x-(4b^4-3a^4)x-12a^2b^2=0 I WILL BE THANKFUL PRIYAL      Log On

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Question 201666: FIND THE VALUE OF 'X' BY QUADRATIC FORMULA
1. 9x^2-9(a+b)x+2a^2+5ab+2ab^2=0
2.a^2b^2x-(4b^4-3a^4)x-12a^2b^2=0
I WILL BE THANKFUL
PRIYAL
Answer by jim_thompson5910(13679) About Me  (Show Source):
You can put this solution on YOUR website!
Simply use the quadratic formula to solve any equation of the form . So for instance, the first equation yields the values , and . Simply plug these values into the quadratic formula to solve for "x". Do the same for the second problem.