SOLUTION: Can you please help me solve this equation. {{{x^2-2x-13=0}}}

Question 200198This question is from textbook Mathematics in Our World
: Can you please help me solve this equation.
This question is from textbook Mathematics in Our World

Found 2 solutions by jim_thompson5910, checkley77:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Start with the given equation.

Notice that the quadratic is in the form of where , , and

Let's use the quadratic formula to solve for "x":

Start with the quadratic formula

Plug in , , and

Negate to get .

Square to get .

Multiply to get

Rewrite as

Add to to get

Multiply and to get .

Simplify the square root (note: If you need help with simplifying square roots, check out this solver)

Break up the fraction.

Reduce.

or Break up the expression.

So the solutions are or

which approximate to or

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
x^2-2x-13=0
Using the quadratic equation: We get:
x=(2+-sqrt[-2^2-4*1*-13])/2*1
x=(2+-sqrt[4+52)/2
x=(2+-sqrt56)/2
x=(2+-7.48)/2
x=(2+7.48)/2
x=9.48/2
x=4.74 ans.
x=(2-9.48)/2
x=-7.48/2
x=-3/74 ans.
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