SOLUTION: I'm not to sure if this is the right section for my question but here goes: I'm working on factorizing using the difference of two squares rule and I need help factorizing this ex

Question 199598: I'm not to sure if this is the right section for my question but here goes:
I'm working on factorizing using the difference of two squares rule and I need help factorizing this expression.
1) (5x-4)^2 - (x-7)^2
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Starting with:
(5x-4)^2 - (x-7)^2
.
Let a = (5x-4)
and b = (x-7)
.
Now, we can rewrite our original equation as:
a^2 - b^2
This, we recognize as being equal to:
(a+b)(a-b)
.
Plugging back in our values of 'a' and 'b' we get:
(a+b)(a-b)
= (5x-4 + x-7)(5x-4 - (x-7))
= (6x-11)(5x-4 - x+7)
= (6x-11)(4x+3) (this is what they're looking for)

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