SOLUTION: 7[2x-4-2(x+1)]=7x+3

Question 199086: 7[2x-4-2(x+1)]=7x+3
Found 2 solutions by jim_thompson5910, RAY100:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
... Start with the given equation.

... Distribute

... Distribute again

Combine like terms on the left side.

Add to both sides.

Subtract from both sides.

Combine like terms on the left side.

Combine like terms on the right side.

Divide both sides by to isolate .

Reduce.

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Answer:

So the solution is which approximates to .
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Use order of operations, PEMDAS
.
7[ 2x - 4 -2(x+1)] =7x +3
.
7[ 2x -4 -2x -2)] = 7x + 3
.
7[ -6] = 7x + 3
.
-42 -3 =-45 =7x
.
-45 / 7 = x
.
check by subst into original eqn,,,,ok
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