SOLUTION: x=(1/20)(y-1)^2+2 what is the vertex,focus,wat direction is opens,axis of symmetry and directrix

Question 197570: x=(1/20)(y-1)^2+2
what is the vertex,focus,wat direction is opens,axis of symmetry and directrix
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x=(1/20)(y-1)^2+2
what is the vertex,focus,what direction is opens,axis of symmetry and directrix
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h = 2 ; k = 1 ; p = 5
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vertex: (2,1)
axis of symmetry: y = 1
opens to the right
directrix: h-p = 2-5 = -3
focus: (h + 5,k) = (7,1)
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Cheers,
Stan H.

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