SOLUTION: x^2+4x+5=0

Question 19747: x^2+4x+5=0
Answer by Alwayscheerful(414) (Show Source): You can put this solution on YOUR website!

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -4 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -4 is + or - .

The solution is

Here's your graph:

If you need further assistance, I can answer questions by email (probably $1 per question) will full detail and explanation.
Hope this helps!
RELATED QUESTIONS
-X^2+4X+5=0 (answered by 24HoursTutor.com)

X^2 + 4X... (answered by edjones)

x^2-4x-5=0 (answered by jim_thompson5910,robertb)

y = x^2 + 4x - 5, y =... (answered by Boreal)

x^2-4x=0 (answered by vleith)

|x^2-4x|<0 (answered by josgarithmetic)

x^2-4x+2=0 (answered by jojo14344)

{{{x^2 + 4x - 2 =... (answered by alicealc)

x^2+4x+2=0 (answered by JBarnum)