SOLUTION: How do I solve this equation? {{{10x^4-19x^2+6=0}}}

Question 197385: How do I solve this equation?

Found 2 solutions by Alan3354, RAY100:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!

,
x = � 2sqrt(5)/5
x = � 3sqrt(2)/2

Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
10x^4 -19x^2 +6 = 0
.
Let y=x^2
.
10 y^2 -19y + 6 = 0
.
(5y-2)(2y-3) = 0
.
y= 2/5, 3/2
.
but y=x^2
.
x^2 = 2/5 , 3/2
.
x = sqrt 2/5 = +/- .632,,,,,or y= sqrt 3/2 = +/- 1.225
.
checking
10(.632^4) -19(.632^2) + 6 = 0,,,ok
10(1.225^4) -19(1.225^2) +6 = 0 ,,,ok
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