SOLUTION: Solve using the quadratic formula: 4x squared+4x=15 I have tried to plug this into the formula, but I don't know if I have to do anything special to the 4x squared, since the

Question 196701This question is from textbook Prentice Hall Algebra 1
: Solve using the quadratic formula:
4x squared+4x=15
I have tried to plug this into the formula, but I don't know if I have to do anything special to the 4x squared, since there is a 4 in there.
Thanks in advance!! :) This question is from textbook Prentice Hall Algebra 1

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Solve using the quadratic formula:
4x squared+4x=15
--------

(2x-3)*(2x+5) = 0
x = 3/2
x = -5/2
--------------
Using quadratic formula:

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=256 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 1.5, -2.5. Here's your graph:

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