SOLUTION: 7x^2-16x-28=0
11x^2=8
Algebra.Com
Question 195697: 7x^2-16x-28=0
11x^2=8
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
# 1
Start with the given equation.
Notice we have a quadratic equation in the form of where , , and
Let's use the quadratic formula to solve for x
Start with the quadratic formula
Plug in , , and
Negate to get .
Square to get .
Multiply to get
Rewrite as
Add to to get
Multiply and to get .
Simplify the square root (note: If you need help with simplifying square roots, check out this solver)
or Break up the expression.
or Reduce
So the answers are or
which approximate to or
# 2
Start with the given equation.
Divide both sides by .
Take the square root of both sides.
or Break up the "plus/minus" to form two equations.
or Simplify the square root.
--------------------------------------
Answer:
So the solutions are or .
RELATED QUESTIONS
x^2+16x+28=0 (answered by solver91311)
3x*(x^2+3x-28)/(x^4-3x^3+7x^2+11x-56)=0 (answered by stanbon)
use any method to solve the equation 7x^2-16x-28=0 (answered by Stitch)
Simplify 3(7x-2) -... (answered by rmromero)
Factoring... (answered by ewatrrr)
Find Complex Roots:
x^4 -11x^2 +28... (answered by richwmiller)
X^4-11x^2+28 (answered by mananth)
Solve : x^2 - 11x =... (answered by stanbon)
11x^2+33x=0 (answered by Linz)