SOLUTION: Solve using the quadratic methods. Thanks!
(x+4)^4-(x+4)^2-6=0
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Question 194754: Solve using the quadratic methods. Thanks!
(x+4)^4-(x+4)^2-6=0
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
^4 - (x + 4)^2 - 6 = 0)
Let ^2)
Factor:
(u - 2) = 0)
or
So:
^2 = 3 \ \ \Rightarrow\ \ x^2 + 8x + 13 = 0)
^2 = 2 \ \ \Rightarrow\ \ x^2 + 8x + 14 = 0)
John
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