SOLUTION: Hello! Graph the following parabola. Calculate and identify vertex and intercepts in graph. Problem - y=x^2+4x+3 y= (x+1) (x+3) = Is this correct s

Question 194613: Hello!
Graph the following parabola. Calculate and identify vertex and intercepts in graph. Problem - y=x^2+4x+3

y= (x+1) (x+3) = Is this correct so far? I'm not sure howto graph this parabola. Can you help me? Thank you!!!

Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
first you have to rewrite this so that the variable y is positive and set this up to complete the square
:

:
vertex is at (-2,1)
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intercepts are found by setting y to zero
:
we know it opens down because it is in the form and coefficient is a negative 1
:
---> so x intercepts are -1,-3: (-1,0)(-3,0)
:

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