SOLUTION: x^2-8x+16=0. Determine the type (real or complex) and number of the solutions of each of the following equations. Justify your answer. Thank You

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Question 194140: x^2-8x+16=0.
Determine the type (real or complex) and number of the solutions of each of the following equations. Justify your answer.
Thank You
Found 2 solutions by josmiceli, jim_thompson5910:
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Complete the square:
Take 1/2 of the coefficient of
square it, and add to both sides

First, subtract from both sides



The left side is now a perfect square


This has double roots, and for each one,
which is real, so 2 real roots
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
From we can see that , , and


Start with the discriminant formula.


Plug in , , and


Square to get


Multiply to get


Subtract from to get


Since the discriminant is equal to zero, this means that there is one real solution.
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