SOLUTION: {{{2x^2-3x+1=0}}}
Use the quadratic formula to solve the following. Leave irrational roots in the simplest radical form.
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Question 19278:
Use the quadratic formula to solve the following. Leave irrational roots in the simplest radical form.
Answer by mmm4444bot(95) (Show Source): You can put this solution on YOUR website!
Hello There:
Do you know what the quadratic formula is? When you have a quadratic equation set equal to zero in the form:
a*x^2 + b*x + c = 0
where you're given the values of a, b, and c, then the formula allows you to find the values of x that make the equation true.
The quadratic formula is: x = [-b +/- sqrt(b^2-4*a*c)]/[2*a]
2*x^2 - 3*x + 1 = 0
In your problem, a = 2, b = -3, and c = 1, so just substitute these values into the formula for a, b, and c.
x = [-(-3) +/- sqrt([-3]^2 - 4)]/[2*(2)]
x = [3 +/- sqrt(9 - 8)]/4
x = [3 +/- sqrt(1)]/4
x = (3 +/- 1)/4
So, there are two solutions:
x = (3 + 1)/4 and x = (3 - 1)/4
x = 4/4 and x = 2/4
x = 1 or x = 1/2
~ Mark
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