SOLUTION: Write a quadratic equation whose roots are 6+4i and 6-4i.
My answer is x^2-12x+40=0
Is this correct?
Algebra.Com
Question 192529This question is from textbook saxon algebra 2
: Write a quadratic equation whose roots are 6+4i and 6-4i.
My answer is x^2-12x+40=0
Is this correct?
This question is from textbook saxon algebra 2
Found 3 solutions by stanbon, Earlsdon, solver91311:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Write a quadratic equation whose roots are 6+4i and 6-4i
-----
y = [(x-6)+4i] * [(x-6)-4i]
y = (x-6)^2 - (4i)^2
y = x^2 - 12x + 36 + 16
y = x^2 -12x + 52
-------------------------
Cheers,
Stan H.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Find the quadratic equation whose roots are:
and
If these are the roots, then the factors of the equation are:
and
To find the equation with these factors, multiply the factors.
One way you could have checked your answer would have been to solve your equation for x using the quadratic formula. Let's see what would we get:
Use and a = 1, b = -12, and c = 40.
or...
and Not quite the same as the given roots.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
I suspect you used the correct process, but you have a little arithmetic problem.
The quadratic trinomial whose factors are x - (6 + 4i) and x - (6 - 4i) is:
\right)\left(x - (6 - 4i)\right) = x^2 - (6 - 4i)x - (6 + 4i)x + (6 + 4i)(6 - 4i))
^2) = x^2 - 12x + (36 - 16(-1)) = x^2 - 12x + 52)
Hence the desired equation is:
John
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