SOLUTION: trying to solve 4x^2+150x=3000

Algebra.Com
Question 189563: trying to solve 4x^2+150x=3000
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

Start with the given equation.


Subtract 3000 from both sides.


Notice we have a quadratic equation in the form of where , , and


Let's use the quadratic formula to solve for x


Start with the quadratic formula


Plug in , , and


Square to get .


Multiply to get


Rewrite as


Add to to get


Multiply and to get .


Simplify the square root


or Break up the expression.


or Reduce.


So the answers are or


which approximate to or

RELATED QUESTIONS

trying to solve the following expression: x^3+4x^2-2x ifx=3, and... (answered by rfer)
I need help trying to solve this. 6x-18/2x^2-5x+3* 4x^2+4x+1/... (answered by jim_thompson5910)
determine whether the following equations are parabolas,circles, ellipses or hyperbolas: (answered by josgarithmetic)
(4x^2+4x+8)+(2x^2+x-7)= also trying to understand how to do it. (answered by ewatrrr)
I am trying this problem solve -5/4x+1/4x=2x+1/2=3/4x and I am very... (answered by Abbey)
Im trying to figure out how to solve this problem. Im not sure how to slove the systems... (answered by checkley77,stanbon)
I am trying to solve for x in the following equation but cant seem to get it right.... (answered by Fombitz)
I am trying to solve this one for homework. y=2+log x y=3/4x+5 Can someone help? (answered by stanbon)
I am trying to solve this equation for y: 2y + 4x =... (answered by ankor@dixie-net.com)