SOLUTION: Solve 4x^3-36x=0
4x(x^2-9)
where do I go from here?
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Question 187600This question is from textbook saxon algebra 2
: Solve 4x^3-36x=0
4x(x^2-9)
where do I go from here?
This question is from textbook saxon algebra 2
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Solve 4x^3-36x=0
4x(x^2-9)
= 4x(x-3)(x+3)
-------------------
A difference of 2 squares is always like that.
x^2 - a^2 = (x-a)*(x+a)
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